SOLUTION OF PROBLEM: 6

Find the value of k such that x +y = k is normal to the parabola (y)sq =12x. (COR/M)

SOLUTION: We already know that y = mx -2am -a(m(cube)) is normal to the parabola y(sq)=4ax. Here in the given problem a=3 and if we compare x +y = k with the standard equation of the normal we get m=-1 and k = -2am -a(m(cube)).

By putting the values of m and a, we get k =9

NOTE: y(sq) is y square and m(cube) is m cube