SOLUTION: The equation will have four different cases
x + y =1, when x>0 and y>0 ( we will draw x + y=1line & will take its part which is lying in Ist quadrant)
x-y =1, when x>0 and y<0 ( we will draw x - y=1line & will take its part which is lying in IVth quadrant)
-x +y =1,when x<0 and y>0 ( we will draw -x + y=1line & will take its part which is lying in IInd quadrant)
-x -y =1,when x<0 and y<0 ( we will draw -x - y=1line & will take its part which is lying in IIIrd quadrant)The enclosed figure will be a square of a side root(2).
Therefore, the area enclose will that of square that is 2 sq units
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